(3B^2/2)-5B-(13/2)=1

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Solution for (3B^2/2)-5B-(13/2)=1 equation: 


B in (-oo:+oo)

(3*B^2)/2-(5*B)-(13/2) = 1 // - 1

(3*B^2)/2-(5*B)-(13/2)-1 = 0

(3*B^2)/2-5*B-13/2-1 = 0

3/2*B^2-5*B-15/2 = 0

DELTA = (-5)^2-(-15/2*3/2*4)

DELTA = 70

DELTA > 0

B = (70^(1/2)+5)/(3/2*2) or B = (5-70^(1/2))/(3/2*2)

B = (70^(1/2)+5)/3 or B = (5-70^(1/2))/3

B in { (5-70^(1/2))/3, (70^(1/2)+5)/3 }

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